Use same printer for both parts
We want to change Aoc.main to take a single printer parameter to simplify the run process.
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@@ -129,7 +129,8 @@ let rec execute_until_halted vm =
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| false -> execute_until_halted (execute_insn vm)
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| false -> execute_until_halted (execute_insn vm)
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(** [string_of_ouput vm] gives the output of [vm]. *)
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(** [string_of_ouput vm] gives the output of [vm]. *)
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let string_of_output vm =
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let part1 vm =
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let vm = execute_until_halted vm in
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List.rev vm.out |> List.map string_of_int |> String.concat ","
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List.rev vm.out |> List.map string_of_int |> String.concat ","
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(** [scan_digit acc ip vm] updates the acc for A so that the output of running
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(** [scan_digit acc ip vm] updates the acc for A so that the output of running
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@@ -159,8 +160,8 @@ let scan_all vm =
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impl 0 (Array.length vm.code - 1)
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impl 0 (Array.length vm.code - 1)
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(** [string_of_a vm] returns the A register of [vm]. *)
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(** [string_of_a vm] returns the A register of [vm]. *)
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let string_of_a vm = string_of_int vm.a
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let part2 vm =
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let vm = scan_all vm in
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string_of_int vm.a
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let _ =
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let _ = Aoc.main vm_of_file [ (Fun.id, part1); (Fun.id, part2) ]
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Aoc.main vm_of_file
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[ (string_of_output, execute_until_halted); (string_of_a, scan_all) ]
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@@ -104,12 +104,12 @@ let find_route_length count grid =
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let part1 count rocks =
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let part1 count rocks =
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match find_route_length count rocks with
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match find_route_length count rocks with
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| None -> failwith "part1"
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| None -> failwith "part1"
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| Some (cost, _) -> cost
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| Some (cost, _) -> string_of_int cost
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(** [part2 start_count grid] returns the location of the first rock to fall into
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(** [part2 start_count grid] returns the location of the first rock to fall into
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[grid] which makes it impossible to get from the top-left to bottom-right.
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[grid] which makes it impossible to get from the top-left to bottom-right.
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*)
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*)
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let part2 start_count grid =
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let part2 width start_count grid =
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(* Implementation notes:
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(* Implementation notes:
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We do this by binary search in impl. The left_count is a known count of
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We do this by binary search in impl. The left_count is a known count of
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@@ -137,16 +137,11 @@ let part2 start_count grid =
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let count = impl start_count (1 + count_rocks 0 0) in
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let count = impl start_count (1 + count_rocks 0 0) in
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match Array.find_index (( = ) (count - 1)) grid.grid with
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match Array.find_index (( = ) (count - 1)) grid.grid with
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| None -> failwith "part2"
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| None -> failwith "part2"
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| Some idx -> idx
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| Some idx -> Printf.sprintf "%d,%d" (idx mod width) (idx / width)
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(** [string_of_idx width idx] prints the (x, y) location for a given index in a
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grid. *)
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let string_of_idx width idx =
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Printf.sprintf "%d,%d" (idx mod width) (idx / width)
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(** Width of grid *)
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(** Width of grid *)
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let width = 71
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let width = 71
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let _ =
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let _ =
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Aoc.main (grid_of_file width)
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Aoc.main (grid_of_file width)
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[ (string_of_int, part1 1024); (string_of_idx width, part2 1024) ]
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[ (Fun.id, part1 1024); (Fun.id, part2 width 1024) ]
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