We want to change Aoc.main to take a single printer parameter to simplify the run process.
148 lines
5.4 KiB
OCaml
148 lines
5.4 KiB
OCaml
(** [pairs_of_ints lst] returns a pair from a list of two elements. *)
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let pairs_of_ints = function
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| [ h; h' ] -> (h, h')
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| _ -> raise (Invalid_argument "pairs_of_ints")
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(** [dijkstra visit check_end states] executes Dijkstra's algorithm.
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[visit cost state] is called to visit [state] with [cost]. It should mark
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[state] as visited, and return a list of [(cost, state)] pairs which contain
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new states to examine. The returned list should be sorted by [cost].
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[check_end state] should return [true] if and only if [state] is an end
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state.
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[states] is a list of [(cost, state)] pairs ordered by [cost].
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[dijkstra] returns [None] if no path is found to the destination. It returns
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[Some (cost, state, remaining_states)] if a route is found. [cost] is the
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cost of getting to [state]. [remaining_states] is a list of the remaining
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states which can be passed back to [dijkstra] if we want to find further
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paths. *)
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let rec dijkstra visit check_end =
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let compare_costs (lhs, _) (rhs, _) = compare lhs rhs in
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function
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| [] -> None
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| (cost, state) :: t ->
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if check_end state then Some (cost, state)
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else
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let new_states = visit cost state |> List.merge compare_costs t in
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dijkstra visit check_end new_states
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type 'a grid = { grid : 'a array; width : int }
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(** [grid_is_valid_pos grid (x, y)] returns true if (x, y) is a valid position
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*)
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let grid_is_valid_pos grid (x, y) =
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x >= 0 && x < grid.width && y >= 0 && y < grid.width
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(** Get the index into the grid from an x, y position. *)
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let grid_idx_by_pos grid (x, y) = x + (y * grid.width)
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(** Set the value of the position (x, y) to v in grid. *)
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let grid_set_by_pos grid p v =
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assert (grid_is_valid_pos grid p);
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let idx = grid_idx_by_pos grid p in
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grid.grid.(idx) <- v
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(** Get the value of the position (x, y) in grid. *)
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let grid_get_by_pos grid p =
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assert (grid_is_valid_pos grid p);
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let idx = grid_idx_by_pos grid p in
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grid.grid.(idx)
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(** [grid_of_rocks w rocks] returns a [w * w] grid with [grid.(x + y * w)]
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indicating whether the space is empty ([=max_int]) or which rock it is (0
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based). *)
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let grid_of_rocks width rocks =
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let grid = { grid = Array.make (width * width) max_int; width } in
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let add_rock idx p = grid_set_by_pos grid p idx in
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List.iteri add_rock rocks;
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grid
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(** [visit grid has_visited count cost pos] visits the location pos marking it
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as visited and returning a list of [(cost, pos)] pairs of next locations to
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examine.
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[grid] is the grid of rocks, [has_visited] is an array of bools indicating
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whether a position has already been visited, and [count] is how many rocks
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have fallen. *)
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let visit grid has_visited count cost state =
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if not (grid_is_valid_pos grid state) then []
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else if has_visited.(grid_idx_by_pos grid state) then []
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else if grid_get_by_pos grid state < count then []
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else
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let x, y = state in
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has_visited.(grid_idx_by_pos grid state) <- true;
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[
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(cost + 1, (x + 1, y));
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(cost + 1, (x - 1, y));
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(cost + 1, (x, y + 1));
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(cost + 1, (x, y - 1));
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]
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(** [grid_of_file w fname] returns a grid of width & height [w] populated with
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rocks described in the file [fname]. *)
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let grid_of_file width fname =
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Aoc.strings_of_file fname
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|> List.map (Aoc.ints_of_string ~sep:",")
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|> List.map pairs_of_ints |> grid_of_rocks width
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(** [find_route_length count grid] calculates the route from the top-left
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position in [grid] to the bottom right if [count] rocks have fallen. It
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returns [None] if no route is possible or [Some (cost, pos)] if the route is
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possible. *)
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let find_route_length count grid =
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let has_visited = Array.make (Array.length grid.grid) false in
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dijkstra
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(visit grid has_visited count)
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(( = ) (grid.width - 1, grid.width - 1))
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[ (0, (0, 0)) ]
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(** [part1 count rocks] returns how long it takes to navigate the grid [rocks]
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when [count] rocks have fallen. *)
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let part1 count rocks =
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match find_route_length count rocks with
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| None -> failwith "part1"
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| Some (cost, _) -> string_of_int cost
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(** [part2 start_count grid] returns the location of the first rock to fall into
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[grid] which makes it impossible to get from the top-left to bottom-right.
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*)
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let part2 width start_count grid =
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(* Implementation notes:
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We do this by binary search in impl. The left_count is a known count of
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rocks that is passable, right_count is a known count that is impassable.
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Once left_count + 1 = right_count we know that right_count is the first
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rock to fall that causes the route to be blocked.
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count_rocks is used to find the number of rocks (and so give an initial
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right_count).
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*)
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let rec count_rocks acc idx =
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if idx >= Array.length grid.grid then acc
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else if grid.grid.(idx) = max_int then count_rocks acc (idx + 1)
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else count_rocks (max acc grid.grid.(idx)) (idx + 1)
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in
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let rec impl left_count right_count =
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if right_count - left_count = 1 then right_count
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else
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let count = (left_count + right_count) / 2 in
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match find_route_length count grid with
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| None -> impl left_count count
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| Some _ -> impl count right_count
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in
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let count = impl start_count (1 + count_rocks 0 0) in
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match Array.find_index (( = ) (count - 1)) grid.grid with
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| None -> failwith "part2"
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| Some idx -> Printf.sprintf "%d,%d" (idx mod width) (idx / width)
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(** Width of grid *)
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let width = 71
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let _ =
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Aoc.main (grid_of_file width)
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[ (Fun.id, part1 1024); (Fun.id, part2 width 1024) ]
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