This lets us validate the solution more easily, and gives us what we actually want which is a pretty picture of the layout.
136 lines
4.0 KiB
OCaml
136 lines
4.0 KiB
OCaml
(*let debugf = Format.ifprintf Format.std_formatter*)
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let pp_card out ((x, y), n) = Format.fprintf out "((%d, %d), %d)" x y n
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let intersects ((x1l, y1b), n1) ((x2l, y2b), n2) =
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let x1r = x1l + n1 in
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let x2r = x2l + n2 in
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let y1t = y1b + n1 in
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let y2t = y2b + n2 in
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let result = x1l < x2r && x1r > x2l && y1t > y2b && y1b < y2t in
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begin
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result
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end
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let rec card_fits size idx placed_cards (x, y) =
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if x + idx > size then false
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else if y + idx > size then false
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else
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match placed_cards with
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| [] -> true
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| h :: t ->
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if intersects h ((x, y), idx) then false else card_fits size idx t (x, y)
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let rec in_card (x, y) cards =
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match cards with
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| [] -> false
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| ((a, b), n) :: t ->
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if x >= a && x < a + n && y >= b && y < b + n then true
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else in_card (x, y) t
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let next_pos size (x, y) cards =
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let rec impl x y =
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if x >= size then impl 0 (y + 1)
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else if in_card (x, y) cards then impl (x + 1) y
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else (x, y)
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in
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impl (x + 1) y
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(*let pp_pos out (x, y) = Format.fprintf out "(@[%d,@ %d@])" x y*)
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let rec find_solutions_impl cards size n idx current_alloc current_pos =
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begin
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(*debugf "find_solutions_impl:@ @[<hov>%a@ %d@ %d@ %d@ %a@ %a@]@;@?"
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(Format.pp_print_array Format.pp_print_int) cards
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size n idx
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(Format.pp_print_list pp_card) current_alloc
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pp_pos current_pos;*)
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if current_pos = (0, size) then current_alloc
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else if idx = 0 then []
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else if cards.(idx) = 0 then
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find_solutions_impl cards size n (idx - 1) current_alloc current_pos
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else if card_fits size idx current_alloc current_pos then begin
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Array.set cards idx (cards.(idx) - 1);
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let new_alloc = (current_pos, idx) :: current_alloc in
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let new_pos = next_pos size current_pos new_alloc in
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let alloc = find_solutions_impl cards size n n new_alloc new_pos in
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Array.set cards idx (cards.(idx) + 1);
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if List.is_empty alloc then
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find_solutions_impl cards size n (idx - 1) current_alloc current_pos
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else alloc
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end
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else find_solutions_impl cards size n (idx - 1) current_alloc current_pos
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end
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let find_solutions cards size =
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find_solutions_impl cards size
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(Array.length cards - 1)
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(Array.length cards - 1)
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[] (0, 0)
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exception Overlapping_value
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let print_solution size cards =
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let array = Array.make (size * size) '.' in
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let set_pos x y c =
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if array.(x + (y * size)) <> '.' then raise Overlapping_value
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else Array.set array (x + (y * size)) c
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in
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let rec write_size x y n =
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if n = 0 then ()
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else begin
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Array.set array (x + (y * size)) (Char.chr (48 + (n mod 10)));
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write_size (x - 1) y (n / 10)
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end
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in
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let rec impl cards =
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match cards with
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| [] -> ()
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| ((x, y), n) :: t -> begin
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if n = 1 then set_pos x y '*'
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else if n = 2 then begin
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set_pos x y '+';
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set_pos (x + 1) y '+';
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set_pos x (y + 1) '+';
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set_pos (x + 1) (y + 1) '+'
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end
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else begin
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set_pos x y '+';
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set_pos (x + n - 1) y '+';
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set_pos x (y + n - 1) '+';
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set_pos (x + n - 1) (y + n - 1) '+';
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for a = 1 to n - 2 do
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set_pos (x + a) y '-';
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set_pos (x + a) (y + n - 1) '-';
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for b = 1 to n - 2 do
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set_pos (x + a) (y + b) ' '
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done;
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set_pos x (y + a) '|';
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set_pos (x + n - 1) (y + a) '|'
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done;
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write_size (x + n - 2) (y + 1) n
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end;
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impl t
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end
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in
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impl cards;
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for y = 0 to size - 1 do
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for x = 0 to size - 1 do
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Format.printf "%c" array.(x + (y * size))
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done;
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Format.printf "\n"
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done
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let n = 8
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let tri_n = (n + 1) * n / 2
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(* Cards is an array initialised so that cards[x] = x for x = [0..9].
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These are the cards we need to fit into the square of length tri_n.
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*)
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let cards = Array.init (n + 1) Fun.id
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let soln = find_solutions cards tri_n
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let () = Format.printf "@[<hov>Base number: %d,@;side length: %d@;" n tri_n
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let () = Format.printf "Solution: %a@]@\n" (Format.pp_print_list pp_card) soln
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let () = print_solution tri_n soln
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