Tidy up 2024 day 11 code.
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@@ -1,13 +1,15 @@
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module IntMap = Map.Make (Int)
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let load_file fname =
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match In_channel.with_open_text fname In_channel.input_line with
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| Some x -> x
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| None -> failwith "load_file"
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(** [apply_n n fn arg] is equivalent to [(fn (fn ... (fn (fn arg))))] where [fn]
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is called [n] times.*)
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let rec apply_n n fn arg = if n <= 0 then arg else apply_n (n - 1) fn (fn arg)
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(** [update_count n o] returns [Some n] if [o] is [None], or [Some (n + x)] if
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[o] is [Some x]. *)
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let update_count n = function None -> Some n | Some x -> Some (x + n)
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(** [map_of_ints lst] returns an [IntMap] with key-value pairs counting how many
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times each integer appears in [lst]. *)
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let map_of_ints =
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let rec impl acc = function
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| [] -> acc
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@@ -15,24 +17,21 @@ let map_of_ints =
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in
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impl IntMap.empty
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(** [calc_blink_rec acc lst] returns an updated map based off [acc] with the
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result of apply a blink step to the stones in [lst]. Entries in [lst] are
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pairs of [(stone id, count)]. [acc] and the resulting map have keys which
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are stone id, and values which are count. *)
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let rec calc_blink_rec acc = function
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| [] -> acc
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| (0, n) :: t -> calc_blink_rec (IntMap.update 1 (update_count n) acc) t
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| (x, n) :: t when Aoc.digits10 x mod 2 = 0 ->
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(** [map_stone id n map] calculates how a collection of stones changes in a
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blink, updating [map] with the result. [id] is the ID of the stone to
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update, [n] is how many stones there are with that ID. *)
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let map_stone id n acc =
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match id with
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| 0 -> IntMap.update 1 (update_count n) acc
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| x when Aoc.digits10 x mod 2 = 0 ->
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let pow = Aoc.pow10 (Aoc.digits10 x / 2) in
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let acc = IntMap.update (x / pow) (update_count n) acc in
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let acc = IntMap.update (x mod pow) (update_count n) acc in
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calc_blink_rec acc t
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| (x, n) :: t ->
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calc_blink_rec (IntMap.update (x * 2024) (update_count n) acc) t
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acc
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| x -> IntMap.update (x * 2024) (update_count n) acc
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(** [calc_blink map] calculates how a collection of stones changes in a blink.
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[map] is a map with key of stone ID, and value number of times that stone
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appears. The result is a map with similar key, value pairs.
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(** [calc_blink map] calculates how a collection of stones changes in a blink,
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returning the result.
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This improves performance because we find that the transformation stones go
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through ends up producing repeated numbers. e.g.: 0 -> 1 -> 2024 -> 20 24 ->
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@@ -41,13 +40,17 @@ let rec calc_blink_rec acc = function
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We also note that despite the problem description saying stones stay in
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order, the result we are asked for (number of stones) does not require them
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to be in order. *)
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let calc_blink map = IntMap.to_list map |> calc_blink_rec IntMap.empty
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let calc_blink map = IntMap.fold map_stone map IntMap.empty
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(** [part n str] returns the number of stones after [n] blinks, given an initial
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string [str] of space seperated stone IDs. *)
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let part n str =
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let map = Aoc.ints_of_string str |> map_of_ints |> apply_n n calc_blink in
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(** [part n lst] returns the number of stones after [n] blinks, given an initial
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list, [lst], of stone IDs. *)
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let part n lst =
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let map = map_of_ints lst |> apply_n n calc_blink in
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IntMap.fold (fun _ v acc -> v + acc) map 0
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(** [ints_of_file fname] returns the integers listed on the first line of
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[fname]. *)
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let ints_of_file fname = Aoc.string_of_file fname |> Aoc.ints_of_string
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let _ =
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Aoc.main load_file [ (string_of_int, part 25); (string_of_int, part 75) ]
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Aoc.main ints_of_file [ (string_of_int, part 25); (string_of_int, part 75) ]
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@@ -6,6 +6,11 @@ let distance1 a b = abs (a - b)
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let strings_of_file fname =
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In_channel.with_open_text fname In_channel.input_lines
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let string_of_file fname =
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match In_channel.with_open_text fname In_channel.input_line with
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| Some x -> x
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| None -> failwith "Aoc.string_of_file"
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let main prep parts =
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try
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match Sys.argv with
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@@ -9,6 +9,9 @@ val strings_of_file : string -> string list
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(** [strings_from_file fname] returns a list of strings from the file [fname].
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Each string represents a line from the file. *)
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val string_of_file : string -> string
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(** [string_of_file fname] returns the first line in [fname]. *)
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val log10i : int -> int
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(** [log10i n] returns the floor of [(log10 (float_of_int n))]. [n] must be
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positive. *)
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