Make 2022 day 19 part 2 more efficient
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@@ -6,16 +6,13 @@
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#include <iostream>
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#include <list>
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#include <map>
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#include <numeric>
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#include <regex>
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#include <set>
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#include <stdexcept>
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#include <utility>
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using Int = std::int32_t;
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using UInt = std::uint32_t;
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enum Resources { Ore, Clay, Obsidian, Geode };
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UInt constexpr ORE{0};
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UInt constexpr CLAY{1};
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UInt constexpr OBSIDIAN{2};
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@@ -49,25 +46,34 @@ struct State
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std::array<uint8_t, resource_count> robots_available_;
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};
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template<typename It1, typename It2>
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auto compare_3way(It1 first1, It1 last1, It2 first2, It2 last2) -> std::strong_ordering
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{
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for (; first1 != last1 && first2 != last2; ++first1, ++first2) {
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if (*first1 < *first2) {
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return std::strong_ordering::less;
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}
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if (*first1 > *first2) {
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return std::strong_ordering::greater;
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}
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}
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if (first1 == last1) {
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return first2 == last2 ? std::strong_ordering::equal : std::strong_ordering::less;
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}
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return std::strong_ordering::greater;
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}
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struct StateCompare
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{
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auto operator()(State const& lhs, State const& rhs) const noexcept -> bool
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{
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for (UInt r{0}; r < resource_count; ++r) {
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if (lhs.resources_available_[r] < rhs.resources_available_[r]) {
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return true;
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}
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if (lhs.resources_available_[r] > rhs.resources_available_[r]) {
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return false;
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}
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if (lhs.robots_available_[r] < rhs.robots_available_[r]) {
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return true;
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}
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if (lhs.robots_available_[r] > rhs.robots_available_[r]) {
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return false;
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}
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auto order = compare_3way(lhs.resources_available_.begin(), lhs.resources_available_.end(),
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rhs.resources_available_.begin(), rhs.resources_available_.end());
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if (order != std::strong_ordering::equal) {
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return order == std::strong_ordering::less;
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}
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return false;
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return std::lexicographical_compare(lhs.robots_available_.begin(), lhs.robots_available_.end(),
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rhs.robots_available_.begin(), rhs.robots_available_.end());
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}
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};
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@@ -75,8 +81,22 @@ using StateSet = std::set<State, StateCompare>;
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auto generate(Costs const& costs) -> UInt
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{
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constexpr UInt total_time{32};
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StateSet next_states;
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// Max cost is indexed by resource, and contains the maximum number of resources we need to build
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// any robot. This provides an upper limit on the maximum number of robots of each type we need
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// to be efficient (as we can only build one robot at a time).
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std::array<UInt, resource_count> max_cost{0, 0, 0, 0};
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for (UInt robot{0}; robot < resource_count; ++robot) {
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for (UInt resource{0}; resource < resource_count; ++resource) {
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max_cost[resource] = std::max(max_cost[resource], costs.costs_[robot][resource]);
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}
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}
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// However as many GEODE robots as possible should be built
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max_cost[GEODE] = std::numeric_limits<UInt>::max();
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constexpr UInt total_time{32}; // Time to run for
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// Use a set for the states to examine to ensure we remove duplicates.
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StateSet next_states; // The states to examine next.
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next_states.insert(State{});
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for (UInt t{0}; t < total_time; ++t) {
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@@ -89,6 +109,9 @@ auto generate(Costs const& costs) -> UInt
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auto built{0};
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auto robots{0};
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for (UInt robot{0}; robot < resource_count; ++robot) {
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if (state.robots_available_[robot] >= max_cost[robot]) {
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continue;
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}
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if (state.robots_available_[robot] != 0) {
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++robots;
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}
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@@ -144,7 +167,7 @@ auto main() -> int
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return EXIT_FAILURE;
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}
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UInt id{static_cast<UInt>(std::stoul(m.str(1)))};
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UInt const id{static_cast<UInt>(std::stoul(m.str(1)))};
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Costs costs;
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costs.costs_[ORE][ORE] = static_cast<UInt>(std::stoul(m.str(2)));
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costs.costs_[CLAY][ORE] = static_cast<UInt>(std::stoul(m.str(3)));
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